The margin or error associated with the confidence interval is 5.62 points
The sample size of the third grade children = 20
The confidence interval for the population mean score = 90%
The mean score = 64 points
The standard deviation = 12 points
The degree of freedom = The sample size - 1
= 20 - 1
= 19
The critical value of t at degree of freedom 19 = ±2.093
The margin error = Critical value of t × [tex]\frac{s}{\sqrt{n} }[/tex]
Substitute the values in the equations
The margin error = 2.093 × [tex]\frac{12}{\sqrt{20} }[/tex]
= 2.093 × 2.68
= 5.62 points
Therefore, the margin error is 5.62 points
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