Question

Given the following code
namespace globalType
{
void printResult();
}
which of the following statements is needed to access printResult?
a. globalType.printResult(): b. globalType:: printResult: c. globalType.printResults(): d. globalType: printResult():

Answer 1

Statements of the form globalType::printResult(); are required to access printResult.

Which of the following claims is used to make accessing all members of the globalType namespace easier?

The output of the statement cout str.* and & are the operators used in pointers when namespace globalType is used and string str = "Gone with the wind" is taken into consideration. In contrast to "&," which provides the address of the variable, * provides the value that is stored at a specific address.

Which syntax should be used when calling static member functions with the class name?

Using the class name to access the static member functions requires the scope resolution operator. It is clear from this that the function belongs in the relevant class.

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