The image of the reflection of QRS over the line t is the same distance
behind the the line t as the pre-image QRS is in front.
The figure that shows a reflection of pre-image QRS over the line t is the option;
- The figure Q'R'S' in the topmost option on the first figure.
Reasons:
The line t is a vertical line, therefore;
Taking the line t as the vertical y-axis, the coordinate of a point (x, y) following a reflection across the y-axis is given as follows;
(x, y) [tex]\underrightarrow{r_{y-axis}}[/tex] (-x, y)
The relative coordinates of the preimage QRS are;
Q(-5, 6), R(-7, 4), and S(-2, 4)
Therefore, we have;
Q(-5, 6) [tex]\underrightarrow{r_{y-axis}}[/tex] Q'(5, 6)
R(-7, 4) [tex]\underrightarrow{r_{y-axis}}[/tex] R'(7, 4)
S(-2, 4) [tex]\underrightarrow{r_{y-axis}}[/tex] S'(2, 4)
The coordinates Q'(5, 6), R'(7, 4), S'(2, 4), corresponds with the coordinates
of the image Q'R'S' in the topmost option of the first figure.
Therefore, the figure that shows a reflection of pre-image QRS over the line t is the topmost option on the first figure.
Learn more about reflection transformation here:
https://brainly.com/question/11570967
