Question

Which part of an atom participates in the reaction shown below?

U235 + n → Xe134 + Sr100 + 2n
A) Nuclei
B) Protons
C) Valence electrons
D) Inner shell electrons

Answer 1

the answer is nuclei

Answer 2

Answer: Option (A) is the correct answer.

Explanation:

A reaction in which nucleus of an atom and a subatomic particle like proton or neutron collide or when any two nuclei combine together then it results in the formation of a new nucleus that is different from its parent nuclei.

For example, $^{235}U + n \rightarrow ^{134}Xe + ^{100}Sr + 2n$

Here, nucleus of Uranium collides with a neutron resulting in formation of a Xenon and Strontium nucleus along with two neutrons.

Therefore, we can conclude that nuclei of an atom participates in the given  reaction.