Question

The coordinates of the vertices of a polygon are (−3, 2) , (2, 3) , (4, 1) , (1, −1) , and (−3, −1). Round each side length to the nearest tenth of a unit.

What is the perimeter of the polygon?

Answer 1

Length of AB is $\sqrt{(y2-y1)^2+(x2-x1)^2}$

AB=$\sqrt{26}$=5.09
BC=$\sqrt{8}$=2.82
CD=$\sqrt{13}$=3.6
DE=4
EA=3

perimeter=add all sides= 18.51