Question

Solve for X. Use the completing the squares method. Round decimals to the nearest tenth: 2x^2+6x=5

Answer 1

Simple...

you have: $2 x^{2} +6x=5$

Remember, you must first move all terms to the left to reduce.

--->>

$2x^{2} +6-5=0$

Using $(\frac{b}{2} ) ^{2}$ in order to create a new term, and then solve for x by completing the square with this term-->>

x= $- \frac{3}{2}, (+/-) \frac{ \sqrt{19} }{2}$

Thus, your answer.