Question

What is the net ionic equation for Al(OH)3 (s) + 3HBr (aq) = AlBr3 (aq) + 3H2O (l)

Answer 1

Al(OH)3+3H+3Br=Al+3Br+H2O. Cancel 3Br both sides
Al(OH)3+3H=Al+2H2O

Answer 2

Answer:

  $Al(OH)_{3}(s)+3H^{+}(aq.)=Al^{3+}(aq.)+3H_{2}O(l)$

Explanation:

• Net ionic equations are written by omitting same ions present in both side of total ionic equation.
• HBr and $AlBr_{3}$ are strong electrolytes. Therefore they are fully dissociated in aqueous solution.
• Total ionic equation: $Al(OH)_{3}(s)+3H^{+}(aq.)+3Br^{-}(aq.)=Al^{3+}(aq.)+3Br^{-}(aq.)+3H_{2}O(l)$
• Net ionic equation (by omitting $Br^{-}$ from both side):

              $Al(OH)_{3}(s)+3H^{+}(aq.)=Al^{3+}(aq.)+3H_{2}O(l)$