Question

How does the value of log2^100 compare with the value of log6^20

Answer 1

Answer:

log_2(100) is about 4 times the value of log_6(20)

Step-by-step explanation:

Lets find the value of both logs and then compare

$log_2(100)$

To find the value we use change of base formula

$log_b(a) = \frac{log(a)}{log(b)}$

$log_2(100) = \frac{log(100)}{log(2)}= 6.643856$

Now we find the value of log_6(20)

$log_6(20) = \frac{log(20)}{log(6)}=1.67195$

6.643556 is approximately four times of 1.67195

So log_2(100) is about 4 times the value of log_6(20)