Question

Josh starts walking at a rate of 2 mph one hour later his sister Mona starts on the same path on her bike riding 10 mph write and equation that but presents the time when Mona catches up to Josh

Answer 1

d = s*t
 
let mona be 1 = d1, s1 & t1
let josh be 2 = d2, s2 & t2

we want distance of mona and josh to be same
 d1=d2
s1*t1 = s2*t2
10(t1) = 2 (t2)