an object is hung from a spring scale while it is immersed in water. the scale reads 5.6 n. the mass of the object is 0.75 kg. what is the density in [x103 kg/m3] of the object?

The gravitational force draws any two mass-containing objects together. The gravitational force is referred to. According to the formula F=Gm1m2r2, the force will always be applied along the line connecting the two masses in the direction of the other mass. It is a force of attraction in nature.

Given,

gravitational force = 5.00N

Mass of the object = 0.5kg

reading when submerged in water = 3.5 N

The loss in weight = 5 - 3.5

= 1.5 N

This loss in water due to buoyancy in water

Loss in weight of water = weight of displaced water

So ww = 1.5 N

Weight of displaced water = w *v * g

Density of water = 10³kg/m³

Thus , 1.5=10³ * v* 10

V = 1.5/10³ * 10 m³

Let density be m/v

=0.5/1.5*10*10³

= 3.33*10³

Therefore density of object is 3.33*10³

The complete question is : The gravitational force exerted on a solid object is 5.00 N. When the object is suspended from a spring scale and submerged in water, the scale reads 3.50 N. Find the density of the object.

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