what is the probability that someone who tests positive has the genetic disease? (enter the value of the probability in decimal format and round the final answer to three decimal places.)

Simply put, probability measures how probable something is to occur. We can discuss the probabilities of various outcomes, or how likely they are, whenever we are unsure of how an event will turn out. Statistics is the study of events subject to probability.

Let E be the people test positive

Let F be the people who has disease

P(F)= 1/10000 = 0.0001

P(E/F)= 99.5% = 0.995

P(E/F bar ) = 0.06 % = 0.0006

Baye's theorem:

P(F/E) = [ P(E/F) * P(F) ] / [ P(E/F) * P(F) + P(E/F bar ) * P( F bar ) ]

conditional probability :

P(B/A) = P ( A [tex]\cap[/tex] B ) / P(A)

Complement rule is given by:

P (F bar ) = 1 - P(F) = 1 - 0.0001 = 0.9999

The probability that someone who tests positive has the genetic disease :

P(F/E) = [ P(E/F) * P(F) ] / [ P(E/F) * P(F) + P(E/F bar ) * P( F bar ) ]

= ( 0.995 * 0.0001 ) / ( 0.995 * 0.0001 + 0.0006 *0.9999)

= 0.142

To learn more about the probability from the given link

https://brainly.com/question/24756209

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