By using t distribution, it can be calculated that
b) Degree of freedom is 65
c) P value of 2.115 at 65 degrees of freedom = 0.0383
What is t-distribution?
t - distribution is used to find the distance between two sample means if the population standard deviation is unknown and it is assumed that the observation comes from a normally distributed population.
b) Here,
Degree of freedom =
[tex]=\frac{(\frac{s_1^2}{n_1} + \frac{s_1^2}{n_2})^2}{\frac{s_1^4}{n_1^2(n_1 -1)} + {\frac{s_2^4}{n_2^2(n_2 -1)}}}\\\\=\frac{(\frac{5.3^2}{35} + \frac{8.8^2}{40})^2}{\frac{5.5^4}{35^2(35 -1)} + {\frac{8.8^4}{40^2(40 -1)}}}[/tex]
= 65
c) The value of test statistic obtained is 2.115
P value of 2.115 at 65 degree of freedom = 0.0383
To learn more about t - distribution, refer to the link-
https://brainly.com/question/24277447
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