step 1 of 4 : state the null and alternative hypotheses in terms of the expected proportion for each day. write your answer as a fraction or a decimal rounded to six decimal places, if necessary.

Respuesta :

By using the concept of testing of hypothesis, the null and alternative hypothesis is given by

[tex]H_0 :p_i = \frac{1}{5}[/tex]

[tex]H_a : p_i \neq \frac{1}{5}[/tex] for atleast one day

What is testing of hypothesis?

Suppose there is a hypothesis and there is a data at hand. Testing of Hypothesis determines whether a particular hypothesis is supported by the data at hand.

The null and alternative hypothesis can be written are as follows-

Null hypothesis: [tex]H_0[/tex] : There is no difference in the number of swimmers from day to day.

Alternative hypothesis: [tex]H_a[/tex] : There is a difference in the number of swimmers from day to day.

[tex]H_0 :p_i = \frac{1}{5}[/tex]

[tex]H_a : p_i \neq \frac{1}{5}[/tex] for atleast one day

To learn more about testing of hypothesis, refer to the link-

https://brainly.com/question/15980493

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Complete Question

The manager of the city pool has scheduled extra lifeguards to be on staff for Saturdays. However, he suspects that Fridays may be more popular than the other weekdays as well. If so, he will hire extra lifeguards for Fridays, too. In order to test his theory that the daily number of swimmers varies on weekdays, he records the number of swimmers each day for the first week of summer. Test the manager’s theory at the 0.10 level of significance.

Swimmers at the City Pool

Monday Tuesday Wednesday Thursday Friday

Number 46 68 43 51 70

Step 1 of 4 :

State the null and alternative hypotheses in terms of the expected proportion for each day. Enter your answer as a fraction or a decimal rounded to six decimal places, if necessary.

H0: pi=⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯

Ha: There is a difference in the number of swimmers from day to day.