two cars leave towns kilometers apart at the same time and travel toward each other. one car's rate is kilometers per hour less than the other's. if they meet in hours, what is the rate of the slower car?

two cars leave towns 340 kilometers apart at the same time and travel toward each other. one car's rate is 18 kilometers per hour less than the other's. if they meet in 2 hours.

Let x be the rate of slower car.

We have two cars heading towards each other. They start 340 km apart and meet up 2 hours later. This means that they are traveling:

340 / 2 = 170 km/hr towards each other.

If the two cars were traveling the same speed, they'd both be going:

170 / 2 = 85 km/hr

We know that one car is traveling 18 km/hr faster than the other car. One way we can account for this is to ± 9 km/hr to the average speed:

85 ± 9 = 94 , 76 km/hr

rate of slower car x = 84 - 9 * 2

x = 76 * 2 km/hr

= 152 km/hr

Therefore The rate of the slower car is 152 km/hr.

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Full question:

two cars leave towns 340 kilometers apart at the same time and travel toward each other. one car's rate is 18 kilometers per hour less than the other's. if they meet in 2 hours, what is the rate of the slower car?