calculate the pressure due to the ocean, in atmospheres, at the bottom of this trench. given that its depth is 11.0 km and assuming the density of seawater is a constant 1.025 x 103 kg/m? all the way down

Respuesta :

Let's first create our working equation. Everyone is aware that pressure is a force applied to a specific area of space. That would be P = F/A in an equation. According to Newton's Second Law of Motion, force equals mass times gravity, or F = mg. So, we can change the first equation to read P = mg/A by substituting F.

Now, the force that a fluid applies to a surface may also be used to calculate pressure. The volume of this fluid can be calculated. The density parameter, p = m/V, is used to relate volume and mass. Volume is the product of the cross-sectional area and the height, to further simplify things in terms of height. So, V = A*h. Following that, the working equation will be derived to be

P = pgh

The pressure that a fluid exerts over a specified height is referred to as hydrostatic pressure. We then locate the density of seawater data from the literature. According to research, saltwater has a density between 1,020 and 1,030 kg/m3. Let's stick with 1.020 kg/m3. Making the units consistent while substituting the values:

P = (1,020 kg/m³) (9.81 m/s2)(11 km)*(1,000 m/1km)

P = 110,068,200 Pa or 110.07 MPa

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