Respuesta :
a) Object maximum height is : 144 feet
b) object hits the ground in : 5.74 seconds
a) t = - [tex]\frac{b}{2a}[/tex]
t = - [tex]\frac{-64}{2(-16)}[/tex]
t = 2 second
h(t) = -16[tex]t^{2}[/tex] + 64t + 80
h(2) = -16([tex]2^{2}[/tex]) + 64(2) + 80
h = -64 + 128 + 80
h = 144 feet
b) Time to maximum height = 2 seconds
Maximum height = 144 ft
Displacement when it hits the ground = -80
-80 = -16[tex]t^{2}[/tex] + 64t + 80
solve for t :
t = 5.74 seconds
A displacement simple definition is what?
A change in an object's position is referred to as "displacement." It is a vector quantity with a magnitude and direction. The symbol for it is an arrow pointing from the initial location to the ending place. For instance, if an object shifts from location A to position B, its position changes.
To know more about displacement visit:
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I understand that the question you are looking for is:
A object is launched directly upward at 64 feet per second (ft/s) from a platform 80 feet high. The equation that models this is given by h(t) = -16[tex]t^{2}[/tex] + 64t + 80.
a) What will the objects maximum height ?
b) How many seconds until the object hits the ground?
