Question

the motion of a piston in an auto engine is simple harmonic. if the piston travels back and forth (side to side) over a distance of 12 cm, and the piston has a mass of 1.5 kg, what is the maximum speed of the piston and the maximum force acting on the piston when the engine is running at 3 800 rpm?

Answer 1

The maximum speed of the piston is 397.73 rad/sec and the maximum force is 12,656.0868 N acting on the piston when the engine is running at 4200 rpm

Since we are given a mass which is 1.5 kg, and an amplitude of 12 cm = 0.12 m. So the angular speed =3 800 rpm = 2*3.14*3800/ 60 = 397.73 rad/sec.Since we know angular speed = √(k/m)

= 397.73 =  √ (k/1.5)

=>158201.08 =k/1.5

=>k=105467.39 N/m

The force will be, F=KA=105467.39 *0.12 = 12,656.0868 N

To know  more about force refers to the link  brainly.com/question/26115859

#SPJ4