bananas are to be cooled from 24 to 13 c at a rate of 215 kg/h by a refrigeration system. the power input to the refrigerator is 1.4 kw. determine the rate of cooling, in kj/min and the cop of the refrigerator. the specific heat of a banana above freezing is 3.35 kj/kg c

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01-12-2022
Engineering

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bananas are to be cooled from 24 to 13 c at a rate of 215 kg/h by a refrigeration system. the power input to the refrigerator is 1.4 kw. determine the rate of cooling, in kj/min and the cop of the refrigerator. the specific heat of a banana above freezing is 3.35 kj/kg c

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rekharaypriti8910 rekharaypriti8910 · Answer 1 · 2022-12-05T18:15:36+01:00

The refrigerator receives a 9.8 kW power input. The proportion of electrical power consumption to heat dissipation is known as the Coefficient of Performance (COP).

It is the criterion used to assess the performance of the air conditioning system. It demonstrates the efficiency of heating and cooling systems. The following list of COP features includes:

The compressor power input to refrigeration output ratio is what determines this.

A rising coefficient of performance (COP) indicates that the cooling output will increase proportionately to the input of electricity. The ratio of electrical power consumption to heat dissipation is known as the Coefficient of Performance (COP). Any system's efficiency will improve with higher COP, and vice versa.

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