After the 4th cut, we will have 1,296 pieces and after the nth cut, we will have [tex]6^{n}[/tex] pieces.
Here, we are given that a sheet of paper is cut into 6 same-size parts. Each of the parts is then cut into 6 same-size parts and so on.
Thus, after one cut we will have 6 pieces
After second cut, we will have 6*6 = 36 pieces
After the third cut, we will have 36*6 = 216 pieces
After the fourth cut, we will have 216*6 = 1,296 pieces
Now, we can clearly see a pattern here. The number of pieces follow a geometric progression with a common ratio of 6.
Thus, after the nth cut, the number of pieces will be-
a[tex]r^{n-1}[/tex]
where a = first term which is 6
and r = common ratio which is also 6
⇒ 6*[tex]6^{n-1}[/tex]
= [tex]6^{n}[/tex]
Thus, after the 4th cut, we will have 1,296 pieces and after the nth cut, we will have [tex]6^{n}[/tex] pieces.
Learn more about geometric progression here-
https://brainly.com/question/24643676
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