The osmotic pressure, π , of a solution of glucose is 88.0 atm . the molarity of the solution at 298 K is 3.60 mol/ L
given that :
osmotic pressure of glucose = 88.0 atm
temperature = 298 K
the expression for the osmotic pressure is as follows :
π = i M R T
where ,
i = van't hoff's factor = 1
R = constant = 0.082 L atm / mol K
T = temperature = 298 K
π = osmotic pressure = 88.0 atm
M = molarity = ?
M = π / i RT
M = 88 / ( 1 × 0.082 × 298 )
M = 88 / 24.43
M = 3.60 mol /L
Thus, the molarity of solution is 3.60 mol/L
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