The maximum error in the calculated area of the disk is 33.93 square cm. The relative error is 0.0148. The percentage error is 1.48%.
a. The area [tex]$\mathrm{A}$[/tex] of a circle with radius [tex]$\mathrm{r}$[/tex] is given by the following formula from Geometry:
[tex]$A=\pi r^2$[/tex]
The question provides us the following information:
radius [tex]$r=27 \mathrm{~cm}$[/tex], maximum radius measurement error [tex]$\Delta r=0.2 \mathrm{~cm}$[/tex]
Using linear differentials we get the error in the calculation of the area of this disk [tex]$\Delta A$[/tex] from (1) as follows:
[tex]$\Delta A=2 \pi r \Delta r \Longrightarrow|\Delta A|=2 \pi r|\Delta r|$[/tex]
Using the information from (2) in (3) yields
[tex]$|\Delta A|=2 \pi(27)(0.2)=33.93 \mathrm{~cm}^2 \text {. }$[/tex]
The maximum error in the calculated area of the disk is 33.93 square [tex]$\mathrm{cm}$[/tex].
b. The relative error is calculated using (1) and [tex]$r=27 \mathrm{~cm}$[/tex] as follows:
Relative Error [tex]$=\frac{|\Delta A|}{A}=\frac{33.93}{\pi\left(27^2\right)}=0.0148$[/tex].
The relative error is 0.0148.
c. The percentage error is the relative error in part b. above multiplied by [tex]$100 \%$[/tex] to give us
Percentage Error [tex]$=100 \% \times$[/tex] Relative Error [tex]$=100 \% \times 0.0148=1.48 \%$[/tex].
The percentage error is [tex]$1.48 \%$[/tex].
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