The calculated torque is 91.55 KN-mm. Yes, the radius of the pulley has an effect on the belt tensions.
For a given frictional torque at the axle, the tension difference between the pull side and the load side is smaller because a larger radius produces a greater moment.
Each pulley's radius is 50 mm;
R1 = R2 = 50 mm.
R1 = 50 mm for the driver's radius
50mm for the radius of the driven,
1800 for the angle of contact (in radians), and
0.3 for the coefficient of friction. T1 = 3KN of permissible stresses Always, T1 is bigger than T2.
Utilizing the formula T1/T2 = e After adding together all the values,
T2 = 1.169KN and 3/T2 = e(0.3)().
Because both pulleys' radiuses are the same, they both experience the same amount of torque (T1–T2). R1
= (T1–T2) (T1–T2). R2
When we add up everything,
(3 - 1.169) X 50
= 91.55 KN-mm.
Learn more about stresses here-
https://brainly.com/question/17252580
#SPJ4