The force exerted by each wire on the other is 2.646N and it is away from each other.
The parallel electricity lines are 270 meters long and spaced 40 centimeters apart.
The power line's current is 140A.
In order to exert force on one power line owing to another,
F = uI1I2L/2r.
Where,
The line's current is I₁ and I₂, respectively.
L is the wire's length.
The distance between them is r.
Assigning values,
F = 4 x π x 10⁻⁷ x 140 x 140 x 270/2 x π x 0.4.
Continuing to solve,
F = 2.646 N.
Because the current is flowing in the same direction, the force will be in the opposite direction. Regardless of the current's direction, the force's magnitude will not change.
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