Force P on the cable if the spring is compressed 0.025 m when the mechanism is in the position shown is 0.198 kN.
The force applied by a spring on objects joined to its finishes is corresponding to the spring's adjustment of a length away from its balance length and is constantly coordinated toward its harmonious position. F = - kx. The proportional constant k is known as the spring steady. It is a proportion of the spring's solidness. Assuming x is positive (uprooting to the right), the subsequent power is negative (toward the left), as well as the other way around. As such, the spring force generally acts to reestablish mass back toward its harmony position. Hence the force P on the cable is 0.198 kN if the spring is compressed 0.025 m when the mechanism is in the position shown.
To learn more about forces and equilibrium,
https://brainly.com/question/12262457
#SPJ4
