Question

An electric iron consumes energy at the rate of 420 W when heating is at the maximum rate and 180 W when heating is at the minimum rate. The applied voltage is 220 V. What is the current in each case?

Answer 1

when heating is at the minimum rate. The applied voltage is 220 V. The current in each case is 271.60 (approx)

P = VI   V is voltage and I is current

then,

I = P/V

when heating is at maximum

current:

I = 420W/220V

=1.9(approx)

resistance:

R = V/I

= 220V/1.9A

=115.78(approx)

when heating in minimum

current:

I = P/V

= 180W/220V

= 0.81 (approx)

resistance:

R = V/I

=220V/0.81A

=271.60 (approx)

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