Respuesta :
Atomic Clock Transition The global standard for time is based on a transition in cesium atoms that occurs when a microwave photon of frequency 9,192,631,770 Hz is absorbed, then the energy difference between the two levels of cesium that correspond with this transition is 38.06 x 10-¹⁴eV
When Cesium atoms are bombarded with microwaves of a certain frequency, this 55th electron goes from one of these hyperfine energy states to the other but then it comes back to the slightly lower energy state and when it does it emits electromagnetic radiation with the exact frequency of 9,192,631,770 Hertz. The time interval in which this wave completes these many cycles is defined as a second. The second is the duration of 9,192,631,770 periods of the radiation corresponding to the transition between the two hyperfine levels of the ground state of the caesium 133 atom.
As we know, energy difference is equal to-
∆E = hf
where h = Planck's constant i.e. 6.626x10-³⁴
f = frequency i.e. 9,192,631,770
∆E = (6.626 x 10-³⁴) * (9,192,631,770)
∆E = 60.91 x 10-³³Joule
To convert joule to electron volt (eV)
1eV = 1.6*10-¹⁹J
∆E = 60.91 x 10-³³/1.6 x 10-¹⁹
∆E = 38.06 x 10-¹⁴eV
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