Question

A glider on an air track is connected by springs to either end of the track. Both springs have the same spring constant, k, and the glider has mass Ma) Determine the frequency of the oscillation, assuming no damping, if k = 125 N/m and M = 210 g .b) It is observed that after 55 oscillations, the amplitude of the oscillation has dropped to one-half of its initial value. Estimate the value of γγ, using x(t)=A* e^γt * cosω′tc) How long does it take the amplitude to decrease to one-quarter of its initial value?

Answer 1

The amplitude drops to one-quarter of the initial value after 102.7 oscillations.

λ=1/51⋅0.20slog(1/2)=−0.68s^-1

Using the previous result we can evaluate the amplitude as a function of time to obtain the elapsed time until the amplitude drops to one-quarter of its initial value,

1/4=Aeλt.

Solving for the time,

t=1/λlog(1/4)=20.4s

Comparing this result with the period,

t=102.7T.

The maximum displacement or distance made by a point on a vibrating body or wave relative to its equilibrium location is known as the amplitude in physics. It is equivalent to the length of the vibration path divided in half. Amplitude is the separation between the wave's resting position and its highest displacement. Frequency is the number of waves that cross a particular place in a second. Period—the length of time needed for a wave cycle to complete

Learn more about amplitude here:

https://brainly.com/question/9525052

#SPJ4