The speed of the arrow as it leaves the bow is 0
75 m/s.
The work done on firing the arrow will be equal to it's kinetic energy responsible for motion. Thus, rating the two values -
F×s = 1/2×m×v², where F is force, s is displacement, m is mass and v is velocity. Keep the values in formula -
Converting cm to m
100 cm to 1 m
78 cm = 0.78 m
100 × 0.78 = 1/2 × 87 × v²
Rewriting the equation according to v²
v² = 87/(78 × 2)
Performing multiplication in denominator of the fraction
v² = 87/156
Performing division on Right Hand Side of the equation
v² = 0.56
v = ✓0.56
Taking square root on Right Hand Side of the equation
v = 0.75 m/s
Hence, the speed is 0.75 m/s.
Learn more about kinetic energy -
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The complete question is -
An 85-g arrow is fired from a bow whose string exerts an average force of 105 n on the arrow over a distance of 75 cm. what is the speed of the arrow as it leaves the bow?
