Respuesta :
The cations and anions in nickeloxide have a 6 coordination number, a p f equals 0 points, and the compound has an fcc structure. 6. 98 point.
As soon as the value is entered, this is for a ket ion and this is for an ion. That equals 4 multiplied by 4 divided by 3 multiplied by 3, as far as we are aware. The pie value multiplied by r, a, and ion radius equals point 14. Given, the value is 0.140. The sum of the cube plus four, divided by three, multiplied by three. The result of multiplying point 14 by the ketion is 0.0 69. The radius is it ionic? This is supplied along with its cube. Therefore, after solving this, we will have 0.0 51 as the v s volume of the sphere value. Now that is equal to the volume of the cube whose volume is v c.
It is a side-facing cube. Therefore, when this equation is solved, the value will be equal to 0.140 + 0.069 entire cubits, which is equivalent to 2 times the product of the radius of the ion and the radius of the cetin. As soon as we enter the value into the formula, which reads that a p f is equal to v s divided by v c, we will have 0.0 73. As a result, we will have 0.051 divided by 0.073, and as a result, we will have ap f equal to 0 + 6. 98. Nickeloxide therefore has an fcc structure, both cations and anions have a coordination number of 6, and a p f is equal to 0 points. 6. 98 point.
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