a container with 3.00 moles of gas has a volume of 60.0 l. with a temperature at 400.k, what is the pressure in atm? your answer should have three significant figures (round your answer to two decimal places). use r

Respuesta :

The pressure of the gas inside the container is 1.6 atm. .This is calculated by the ideal  gas law.

Ideal gas law states that the pressure of ideal gas is directly proportional to the absolute temperature of the gas. The ideal gas law also called the general gas equation. This is the equation of state of a hypothetical ideal gas. It is a good approximation of the behavior of many gases under many conditions . The expression for ideal gas law is,

          PV = nRT

where,  P is the pressure of the gas

             V is the volume of the gas

             n is the number of moles of the gas

             T is the temperature of the gas

A container with 3.00 moles of gas has a volume of 60.0L with a temperature at 400 K. To find the pressure of the gas we have to apply all these value in ideal gas law.

n = 3.0 moles

V = 60.0 L

T = 400 K

From PV = nRT,

           P = n RT / V

         = (3.0 mole) (0.0821 L-atm. /K-mole)(400 K) / 60.0L

         = 1.642 atm.

          = 1.6 atm.

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