A liquid of constant density rho and constant viscosity Î¼ flows down a wide, long inclined flat plate. The plate makes an angle Î¸ with the horizontal. The velocity components do not change in the direction of the plate, and the fluid depth, h, normal to the plate is constant. There is negligible shear stress by the air on the fluid. Find the velocity profile u(y), where u is the velocity parallel to the plate and y is measured perpendicular to the plate. Write an expression for the volume flow rate per unit width of the plate.

The velocity profile u(y) is defined as V = (alpha)*g*sin(alpha)*h^3/3M, where u is the velocity measured parallel to the plate and y is measured perpendicular to the plate. The air just slightly shear stresses the fluid.

Velocity is a vector measurement of an object's rate of motion and direction of motion. The magnitude and direction must therefore be understood in order to calculate the velocity according to this criterion. It is possible to describe shearing stress, also known as shear stress, as "a type of stress that acts coplanar with cross section of material." Shear forces resulted in shear stress. They are a pair of forces that have the same magnitude and are directed in the opposite direction and operate on opposite sides of a body. A vector quantity is shear stress.

Alpha = g*sin(alpha)*h2/2M [y - y^3/3h^2]

V = (alpha)*g*sin(alpha)*h2/2M

Alpha = g*sin(alpha)*h^3/3M

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