Question

Suppose you go to work for a company that pays one penny on the first day, 2 cents on the second day, 4 cents on the third day and so on.
Hint: use an= a1 (r)^n-1 and Sn= a1 (1-r^n) / 1 - r

A. If the daily wage keeps doubling, what would your income be on day 31? Give your answer in dollars NOT pennies.

Income on day 31 = $ __________

B. If the daily wage keeps doubling, what will your total income be for working 31 days? Give your answer in dollars NOT pennies.

Total Income for working 31 days = $ _________

Answer 1

Using the given function, the income for day 31 is

• $10,737,418.24

the total Income for working 31 days is

• $21 474 836.47

How to find the income on day 31

Using the given function an = a1 (r)^n-1

where

a1 = first day = 1

r = common ratio = 2

The income on day 31, n = 31

= 1 * 2^(31 - 1)

= 2^30

= 1,073,741,824 cents

= $10,737,418.24

Total Income for working 31 days n = 31

Using Sn= a1 (1-r^n) / 1 - r

Sn = (1 * (1 - 2^31)) / (1 - 2)

Sn = (1 - 2^31)) / - 1

Sn = (1 - 2147483648) /-1

Sn = 2147483647

Sn = 2,147,483,647 cents

Sn = $21 474 836.47

Learn more about geometric progression at:

https://brainly.com/question/12006112

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