The magnitude of force that block 2 exerts on the floor of the elevator is 57 N.
Mass of block 1 = m = 2Kg
Mass of block 2 = M = 3Kg
Acceleration of the elevator = 1.6 m/s
The magnitude of force exerted by block 2 = N =
= Using Newton's second law of motion
= N - w = (m + M) X a
= N - (m + M) X g = (m + M) X a
And we know that total force = m X a
= N = (m + M) X (g + a)
= N = (3+2) X (9.8 + 1.6)
= N = 5 X 11.4
= N = 57 N
Thus, the force exerted by block 2 on the elevator floor is 57 Newtons.
The complete question:
two blocks are stacked on top of each other on the floor of an elevator as shown. the mass of block 2 (bottom) is 3.0 kg and the mass of block 1 (upper) is 2.0 kg. the elevator is accelerating upwards at a constant rate of 1.6 m/s2. What is the force exerted by block 2 on the floor of the elevator?
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