Question

g an apple pie in a 9.00 in diameter plate is placed upon a rotating tray. then, the tray is rotated such that the rim of the pie plate moves through a distance of 158 in. express the angular distance that the pie plate has moved through in revolutions, radians, and degrees.

Answer 1

The angular distance should be the angular distance that the pie plate has moved through in revolutions, radians, and degrees are 5.59 revolution and  2012.4° respectively.

In revolution, θ = 8.24 revolution.

In radian = θ = 57.78 rad.

In degree θ = 2966.4°.

Calculation of the angular distance:

Since

Pie diameter = 9 in

So,  the circumference of the pie should be

P = πd = 9π in

And, rim of the pie rotates 158 in,

So,

1 Revolution of the pie is 9π in,

So, for 158 it should be

= 158 in / 9π in revolution

= 5.59 revolution

Now in the case when

1 revolution is 2πrad

So,

5.59 revolution = 5.59 × 2π = 87.79 rad.

And also, 1 revolution is 360°

5.59 revolution = 5.59 × 360 = 2012.4°

Learn more about revolutions here:-https://brainly.com/question/111640

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