Question

ethane is burned with 50% excess air. the percentage conversion of the ethane is 90%; of the ethane burned, 25% reacts to form co and the balance reacts to form co2. calculate the molar composition of the stack gas on a dry basis and the mole ratio of water to dry stack gas.

Answer 1

The molar composition of the stack gas on a dry basis and the mole ratio of water to dry stack gas is 0.1143.

the equation is,

C2H6 + 7/202 → 2CO2 + 3H2O

1mol      3.5mol    2mol      3mol

for 100 mol GHG, & required = 100×3.5 mol

                           O2 required = 350 mol

                                    O₂ fed = 1.5×350 mol

                                    O₂ fed =525 mol

N2 fed = 0.79/0.21 X 525 mol

N2 fed =1975mol

Mole ratio of water to dry stack gas = Moles of water/Moles of dry stack

                                                                                          gas Without water                                  

                                                            =270 mol / 2362.5 mol

                                                            = 0.1143

Mole ratio water to of dry stack gas = 0.1143

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