Consider a process carried out on 1.00 mol of a monatomic ideal gas by the following two different pathways. The first pathwayis A (3.00 atm, 20.0 L) to C (1.00 atm, 20.0 L) to D (1.00 atm, 50.0 L); and the second pathway is A (3.00 atm, 20.0 L) to B (3.00atm, 50.0 L) to D (1.00 atm, 50.0 L). In each case, the gas is taken from state A to state D.33. Calculate wAB.a. 0b. 90 L•atmc. –90 L•atmd. –30 L•atme. 30 L•atm34. Calculate wAC.a. 0b. 30 L•atmc. –30 L•atmd. 90 L•atme. –90 L•atm35. Calculate q AB.a. 135 L•atmb. –135 L•atmc. 225 L•atmd. –225 L•atme. none of these36. Calculate q AC.a. 60 L•atmb. 100 L•atmc. –60 L•atmd. –100 L•atme. none of these

Consider a monatomic perfect gas with m-mean particles that don't interact and a resting mass center. An ion with only one atom is referred to as a monatomic ion or simple ion. A polyatomic ion is one that has more than one atom, even if they are all from the same element.

From the information provided:

The first route:

A (1 atm, 20 L), C (3 atm), and D (1 atm, 50 L)

The second route:

A (3 atm, 50 L), B (3 atm, 20 L), and D ( 1 atm, 50 L)

Because one mole equals one mole,

to locate wAB;

The conversion is depicted as A B occurring under constant pressure.

∴

Pressure x Volume Change = wAB

V2 - V1 = wAB

atm = wAB ( 50 L - 20 L)

atm = wAB ( 30 L)

wAB=90 L.atm

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