Lactose is present, but glucose is not: strong transcription of the lac operon occurs. Because the inducer (allolactose) is present, the lac repressor is released from the operator.
Because glucose is not present, cAMP levels are high, indicating that CAP is active and bound to the DNA. It's expressed only when lactose is present and glucose is absent.
in this case we conclude by these terms
I- = always on
Oc = always on
Z- = no lactose
Is = super repressor = always off, can only be inhibited by Oc
Examples:
W/ lactose & w/out lactose
F'-I+/I-O+Z- no & no
F'-Is/I-OcZ+. yes & yes
I +O+Z+/F' I-O+Z+. yes & no
I-OcZ-/F' I-Oc Z- no no
I-OcZ+/F' I-O+Z+. yes & yes
IsOcZ-/F' IsO+Z+. no & no
Without the regulator repressor, enzyme production will be constitutive;
enzyme production is still repressible.
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