The integral of f (z) around the positively oriented circle |z| = 3 is equal to 2πi times the sum of the residues of the poles of f (z) inside the circle.
The poles of f (z) inside the circle are z = 0 and z = −1/2.
The residue at z = 0 is f (0) = 0.
The residue at z = −1/2 is f (−1/2) = −7/16.
Therefore, the integral of f (z) around the positively oriented circle |z| = 3 is equal to 2πi (−7/16) = −7πi/8.
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