Question

An airplane flies 370 miles from point A to point B with a bearing of 24" . It then flies 240 miles from point B to point € with a bearing 0f 37" Draw diagram of the information. Then find the distance from point A to point C and the bearing from point A to point C

Answer 1

The distance from point A to point C and the bearing from point A to point C is 229.5 miles.

Given that:

AB = 370 miles

angle A = 24 degrees

BC = 240 miles

angle B = 37 degrees 

To determine the distance from point A to C, we can use the cosine law since we are given two angles and two sides of a regular triangle. 

The angle opposite side AC is angle B which is equal to 37 degrees. 

(AC)^2 =(AB)^2 + (BC)^2 - 2(AB)(BC)cos(B)

Now we have to solve for AC:

(AC)^2 =(370)^2 + (240)^2 - 2(370)(240)cos(37) 

AC = 229.48 miles.

Hence the answer is, the distance from point A to point C and the bearing from point A to point C is 229.5 miles. 

To learn more about angels click here https://brainly.com/question/28469016

#SPJ4