You may simply use the common equation y=mx+b as this is a linear (non-exponential) population problem. Where m=(population change/year change) 420 more people were added to the population between 1998 and 1991.
According to the data you were given (4130-3710). So, (420/7)\s= 60 = m. assuming that 1991's growth rate was the same as that of 1990. The initial population would then be (3710-60) or 3650, which would be your "b" number because at t=0 P(t) = 3650. The final equation is P(t) = 60t + 3650 as a result of this. The population in 1991, as determined by checking the response at t=1, was 3710.
Let x be the number of years since the year 1990 and y be the number of population measurements in order to obtain the formula for the population that changes linearly.1994 saw x = 4, y = 3080, while 1997 saw x = 7, y = 3320. On a graph, we recently received the points (4, 3080) and (7, 3320).By inserting both points into the equation m =(3080- 3320) / (4 -7) m =(-240) /(-3) and m=80, the slope formula is used.
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