Well here i can't provide the diagram of the starting material is a 6 C ring where C 1 has a wedged bond to bromide (Br) and a dashed bond to hydrogen. moving counterclockwise, C 2 has a wedged bond to methyl and a dashed bond to hydrogen. this reacts with c h 3 o n a and methanol to form the product.
Bromide is the negatively charged member of the halogen group and is a form of Bromine element. Bromine's atomic no is 35 and atomic mass is 79.904 u.
Methanol is first of all is a organic chemical with the formula CH₃OH. It is an aliphatic alcohol which is colorless and volatile in nature.
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