What is the polar form of negative 9 minus 9 i startroot 3 endroot ?

Trigonometric Identities are equality statements that hold true for all values of the variables in the equation and that use trigonometry functions.

There are numerous distinctive trigonometric identities that relate to a triangle's side length and angle.

So, we have -9 - 9√3i:

This quantity has a modulus.

|-9 - 9√3 i| = √((-9)² + (-9√3)²) = √324 = 18

And argument θ to the effect:

tan(θ) = (-9√3) / (-9) = √3

We anticipate that will be between -π and -π/2 radians since -9-9√3i lies in the third quadrant of the complex plane, so that:

θ = arctan(√3) - π = π/3 - π = -2π/3

The polar form is then:

18 (cos(-2π/3) + i sin(-2π/3))

And since -2π/3 is the same angle as 2π - 2π/3 = 4π/3, the right answer is: 18 (cos(4π/3) + i sin(4π/3))

Therefore, using trigonometry identities, we know that the polar form of -9-9√3i is (D) 18 (cos(4π/3) + isin(4π/3)).

Know more about trigonometric identities here:

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Complete question:
What is the polar form of Negative 9 minus 9 I StartRoot 3 EndRoot?

a. 9 (cosine (StartFraction pi over 3 EndFraction) + I sine (StartFraction pi Over 3 EndFraction) )

b. 9 (cosine (StartFraction 4 pi over 3 EndFraction) + I sine (StartFraction 4 pi Over 3 EndFraction) )

c. 18 (cosine (StartFraction pi over 3 EndFraction) + I sine (StartFraction pi Over 3 EndFraction) )

d. 18 (cosine (StartFraction 4 pi over 3 EndFraction) + I sine (StartFraction 4 pi Over 3 EndFraction) )