Respuesta :
Na2so3 is the empirical formula for a compound that, by mass, contains 29% NA, 41% S, and 30%.
What is empirical formula of a compound?
The empirical formula of a chemical compound in chemistry is the simplest whole number ratio of atoms in a compound. Two simple examples of this concept are the empirical formulas of sulfur monoxide, SO, and disulfur dioxide, S2O2. An empirical formula is a compound's chemical formula that only specifies the ratios of the elements it contains and not the precise number or arrangement of atoms. This would be the compound's element with the lowest whole number ratio.
How can you determine a compound's empirical formula?
1. To solve an empirical formula problem, you must first determine the mass percentage of the constituent constituents.
2. Next, convert the percentage to grams.
3. Subtract each mass from its corresponding molar mass.
4. Select the moles answer that is the smallest and divide all numbers by that.
Briefing:
1. Change every percentage to grams.
29% Na = 0.29g
41% S = 0.41 g S
30% O = 0.30 g O
2. Change every amount to moles.
0.29 g Na = 0.01261… moles Na
0.41 g S = 0.01278… moles S
0.30 g O = 0.01875 moles O
3. Divide each mole by the smallest one, then roughly
0.01261 mol Na /0.01261 approximately 1
0.001278 mol S/0.01261 approximately 1(rounded from 1.01348…)
0.01875 mol O/0.01261 approximately 1.5(rounded from 1.486915
4. Since one of the elements was rounded to a non-whole integer, we must multiply each element by 2 to obtain whole numbers.
Na: 1 * 2 = 2
S: 1 * 2 = 2
O: 1.5 * 2 = 3
5. Based on the numbers above, create the equation using subscripts for each element.
6. sodium thiosulfate (Na2S2O3)
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