The standard deviation of the number of days absent is found as 1.1616.
For the stated question-
Number of Days Absent/Probability
Thus, the mean is found as;
Mean = (0x0.60) + (1x0.20) + (2x0.12) + (3x0.04) + (4x0.04)
Mean = 0.72
Standard deviation σ = (0-0.72)² x 0.60 + (1-0.72)² × 0.20 + (2-0.72)² × 0.12 + (3-0.72)² × 0.04 + (4-0.72)² × 0.04
Standard deviation = 1.1616
Thus, the standard deviation of the number of days absent is found as 1.1616.
To know more about the standard deviation, here
https://brainly.com/question/475676
#SPJ4
The complete question is-
A company is studying the number of monthly absences among its 125 employees. The following probability distribution shows the likelihood that people were absent 0, 1, 2, 3, 4, or 5 days last month.
Number of Days Absent/Probability
0 0.60
1 0.20
2 0.12
3 0.04
4 0.04
5 0.00
What is the standard deviation of the number of days absent?