contestada

the specific heat of solid water and liquid watrer are 2.03 jgc and 4.18 g c respectively. calculate the heat of fusion of water in j/g

Respuesta :

The heat of fusion of water is 335.091 j/g when considering the concept of calorimetry, sensible heat, and latent heat.

What is a simple definition of calorimetry?

Calorimetry is a branch of science that measures a body's status with regard to temperature in order to look at changes in its physical and chemical composition. The changes could be chemical, like burning, acid-base neutralization, or physical, such melting or evaporation.

What is the calorimetry's fundamental tenet?

Calorimeter Theory

While the body at a lower temperature absorbs heat, the body at a higher temperature releases heat. The law of conservation of energy is demonstrated by the principle of calorimetry, which states that the total amount of heat lost by a heated body is equal to

Briefing:

The total heat required is calculated as:

Total heat required= Q1 + Q2 + Q3

Total heat required= 2.50 kJ + 49.3 g× ΔHfus + 9.21 kJ

Heating a 49.3 g sample of g ice from -25.0 °C to water at 44.7 °C requires 28.23 kJ of heat. This is, the total heat required is 28.23 kJ. Then:

28.23 kJ= 2.50 kJ + 49.3 g× ΔHfus + 9.21 kJ

Solving:

28.23 kJ= 11.71 kJ + 49.3 g× ΔHfus

28.23 kJ- 11.71 kJ = 49.3 g× ΔHfus

16.52 kJ = 49.3 g× ΔHfus

16.52 kJ / 49.3 g= ΔHfus

0.335091= 335.091  =ΔHfus

In summary, the heat of fusion of water is 335.091  .

To know more about calorimetry visit:

https://brainly.com/question/11477213

#SPJ4

RELAXING NOICE
Relax