Question

a planet with a radius of 6.00 x 107 m has a gravitational field of magnitude 30.0 m/s? at the surface. what is the escape speed from the planet?

Answer 1

The escape speed of the planet is 756.60 m/s

How to calculate escape speed from the planet ?

The earth's surface escape speed is roughly 11.2 km/s. This means that an object must have a minimum beginning velocity of 11.2 km/s in order to escape the gravity of the earth and journey into limitless space.

The minimum speed required for a free, unpropelled object to be able to escape the gravitational pull of a primary body and travel an infinite distance from it is known as the escape velocity or escape speed in celestial mechanics. Typically, it is expressed as an ideal speed that disregards atmospheric friction.

Given ,

Gravitational magnitude = 30.00m/s

Escape speed from planet = √[2×30/6*107][

√[2×30.00] /6 ×107

= 756.60 m/s

Therefore Escape speed from planet is 42.4264

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