2Pb(s) + O2(g) ⟶ 2PbO(s) ... balanced equation
Since there is an excess of O2, we need not worry about limiting reactants, and yield will depend only on Pb.
atomic mass Pb = 207.2 g/mol
atomic mass PbO = 223.2 g/mol
451.4 g Pb x 1 mol Pb / 207.2 g x 2 mol PbO / 2 mol Pb x 223.2 g PbO/mol = 486.3 g PbO = theoretical yield
% yield = actual yield / theoretical yield (x100%) = 339.4 g / 486.3 g (x100%) = 69.8% yield
What is atomic mass?
The atomic mass of a chemical element, expressed in atomic mass units. This roughly corresponds to the number of protons and neutrons in the atom (mass number), or the average number taking into account the relative abundance of different isotopes.
Therefore, % yield = actual yield / theoretical yield (x100%) = 339.4 g / 486.3 g (x100%) = 69.8% yield
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