a 47.2-ml sample of naoh is titrated with 0.624 m hbr. 27.4 ml of the acid are required to reach the equivalence point. what is the molarity of the base?

The number of moles of dissolved solute per litre of solution is the definition of molarity, a unit of concentration. Molarity is defined as the number of millimoles per millilitre of solution by dividing the number of moles and the volume by 1000. A precise 1.000 mole of KCl (74.55 g) must be dissolved in a quantity of water or another solvent to produce a precise 1.000 litre of solution in order to create a 1.000 M solution of KCl.

In actuality, this concentration unit is frequently abused. Since KCl is totally dissociated, the solution, for instance, with water as the solvent, is exactly 1.000 M in K+ and 1.000 M in Cl.

Recall that: mole = molarity x volume

Also; molarity = mole/volume

Mole of 0.624 M, 27.4 mL HBr = 0.624 x 27.4/1000

= 0.017 mol

If the mole of HBr is 0.017 mol, the equivalent mole of NaOH will also be 0.017 mol.

0.017 mol of 47.2 mL (0.0472 L) NaOH would molarity of:

0.017/0.0472 = 0.36 M

In other words, the molarity of the NaOH is 0.36 M.

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