Question

An 82.0-kg person rides on a carnival ride in a 45.0-kg basket supported by a single chain. When the ride reaches its top speed, the basket moves at a constant speed in a horizontal circle with a radius of 7.10 m. At this point, the chain supporting the basket is at a 45.0 angle to the vertical.

Answer 1

The chain supporting the basket is at a 45° angle to the vertical and horizontal component is 1244.6N.

What is constant speed?

When an object's speed stays the same and neither increases nor decreases, we say it is moving at a constant speed.

Mass of the person is 82kg and mass of the basket is 45 kg.

New total mass, M = 82+45 = 127kg.

Here, Fe is centrifugal force

v is velocity of the person

r is radius of the circle,

r = 7.1m

Now, Tsin 45° = Mg [ here Mg is weight of person and basket]

T = Mg/sin 45° = Mg√2

Now, vertical component of the tension,

Fy = Tsin 45° = Mg = (127×9.8)kg-m/s²

Fy = 1244.6N

Now, horizontal component,

Fx = Tcos 45°

Fx = Mg/Tan 45°

Fx = Mg/1

Fx = 1244.6N

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