the typing speeds for the students in a typing class is normally distributed with mean 44 (μ) words per minute and standard deviation 6 (σ) words per minute. what is the probability that a randomly selected student has a typing speed of less than 38 words per minute? use the empirical rule provide the final answer as a percent. if necessary round the percent to the nearest whole number.

A probability distribution that is symmetric about the mean is the normal distribution, sometimes referred to as the Gaussian distribution. It demonstrates that data that are close to the mean occur more frequently than data that are far from the mean. The normal distribution appears as a "bell curve" on a graph.

The formula for z-score is z = (x -μ)/σ

Where,

Z is standard score.

x is observed value.

μ is mean of the sample.

σ is standard deviation of the sample.

According to the given question.

The mean of the distribution is μ = 44

The standard deviation of the distribution is σ = 6

The observed value is x = 38

Therefore, z-score = (38 -44)/6 = -1

So, the are P(z > -1) = 15.87%

Hence, the probability that a randomly selected student has a typing speed of less than 38 words per minute is 15.87%.

To learn more about z-score and probability, click on below link:

https://brainly.com/question/14174044

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